Can any one solve this math problem?

Please show your work after you are done, i will check the thread after a few days

There are 6 ladders, and a wall 200m high. These ladders are leaning against each other but will collapse if too much pressure is applied. The height from the (flat) floor to the intersection point of the 2 ladders is 7 ft, the distance between the 2 WALLS is 22m. How can you climb above 200 with these 6 LADDERS?

Ladder 1 is very sturdy but tends to snap under pressure. The rungs creak severely with high usage and the supporting frame constantly requires a review.

Ladder 2 hasn't been tested under this amount of weight before. It looks like a good ladder but is starting to show signs of wear and tear.

Ladder 3 has been imported from overseas. It is made of a different type of wood and you suspect the other ladders are concerned it will take its fair load.

Ladder 4 doesn't look much like a ladder at all, although for some reason people once held high hopes for this ladder as being the future of all ladders.

Ladder 5 is extremely good, shiny, well engraved and admired by all. However it is prone to collapsing inexplicably when positioned anywhere other than fifth in the sequence.

Ladder 6 is highly flamable. When using you must be careful not to expose the wood to any root.

Can you take a long run-up?

Forget them all, ladder 11 will do the job on its own.

I heard the 10th ladder partnership is averaging more than the opening ladder partnership this year - as beamer says, let the ladders fall.

Hehehe, nice work, Gaz.  

Unfortunately the 11th ladder snapped in half and is now in the shed undergoing urgent repairs.

You must solve the problem using only the 6 ladders. Please show your working.

I raised this problem with a few of the more intellectually inclined in the current Australian Team only for them to come back to me with this paradigm-shifting missive.



Obviously in this case they have adhered to the mathematician's battle cry 'go forth and generalize', but it is easy to see how to apply these stunning and elegant results to the above problem by considering each ladder a unique point in some uncountable Hilbert space isomorphic to BMO and then applying standard parabolic theory. Hence, a solution exists and is cyclical [J. A. Anderson, Arch. Ration. Mech. Anal, 2007].

These were the attachments

You rung?

The answer is 42

lardbucket wrote:You rung?

I scaffolded.

Well this hasn't climbed to any heights

Well as Edmund and I are the forum snakes...